Answer:
2/3
Step-by-step explanation:
List all the possible sums. If it helps, make a table:
[tex]\left[\begin{array}{ccccccc} &1&2&3&4&5&6\\1&2&3&4&5&6&7\\2&3&4&5&6&7&8\\3&4&5&6&7&8&9\\4&5&6&7&8&9&10\\5&6&7&8&9&10&11\\6&7&8&9&10&11&12\end{array}\right][/tex]
There are 36 total possible sums. Of those, 18 are even, and 6 are odd but multiples of 3.
Therefore, the probability is:
P = (18 + 6) / 36
P = 24 / 36
P = 2 / 3
