Answer:
V = 331.13 mL of 50 by mass NO3 solution
Explanation:
∴ δ sln = 2.00 g/mL
∴ %m HNO3 = 50% = ( mass HNO3 / mass sln ) × 100
∴ V required sln = 500 mL
∴ δ HNO3 = 1.51 g/mL.......from literature
⇒ V sln = mass sln / δ sln = 500 mL
⇒ mass sln = (500 mL )×( 2 g/mL ) = 1000 g sln
⇒ mass HNO3 = ( 0.5 )×(1000 g) = 500 g HNO3
⇒ V HNO3 = ( 500 g HNO3 )×(ml HNO3/1.51 g ) = 331.13 mL
