Step-by-step explanation:
Given :
ΔBCD ≈ ΔFGE
[tex]\frac{BC}{FG}=\frac{BD}{EF}[/tex]
[tex]\frac{39}{4x+2}=\frac{42}{5x-2}[/tex]
[tex]39\times (5x-2)=42\times (4x+2)[/tex]
[tex]195x-78=168x+84[/tex]
[tex]195x-168x=84+78[/tex]
[tex]27x=162[/tex]
[tex]x=\frac{162}{27}=6[/tex]
x = 6
FG = 4x + 2 = 4 × 6 +2 = 26
EF = 5x - 2 = 5 × 6 -2 = 28
