Answer:
[tex]\sqrt{-6 + \frac{y}{3}} = x[/tex]
Step-by-step explanation:
y = 18 + 3x²
- 18 - 18
__________
[tex]\frac{-18 + y}{3} = \frac{3x^2}{3} \\ \\ -6 + \frac{y}{3} = x^2 \\ \\ \sqrt{-6 + \frac{y}{3}} = x[/tex]
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