Answer:
The diameter of the track is 49 m.
Step-by-step explanation:
The circumference of the track = 154 m
The Circumference of a Circle = 2 π r
⇒[tex]2 \times \frac{22}{7} \times r = 154[/tex]
⇒[tex]r = \frac{154 \times 7}{2 \times 22} = 24.5[/tex]
or, radius of the circle = 24.5 m
Now, Diameter = 2 x Radius
or, Diameter = 2 x 24. 5 m
= 49 m
Hence, the diameter of the track is 49 m.
