Answer:
d = 3
Step-by-step explanation:
Firstly eliminate the modulus sign by multiplying the value inside with (-1)
; |2d - 6| = -2d + 6...then substitute it back into the equation,
; 3(-2d + 6) + 2 = 2
; -6d + 18 + 2 = 2
; -6d = -18 - 2 + 2
; -6d = -18
;Hence the value of...; d = 3
