Answer:
[tex]\large\boxed{(f\circ g)(x)=-15x+14}[/tex]
Step-by-step explanation:
[tex]f(x)=-5x+9\\\\g(x)=3x-1\\\\(f\circ g)(x)=f\bigg(g(x)\bigg)-\text{put}\ x=g(x)\ \text{in}\ f(x):\\\\(f\circ g)(x)=-5(g(x))+9=-5(3x-1)+9\qquad\text{use the distributive property}\\\\=(-5)(3x)+(-5)(-1)+9=-15x+5+9=-15x+14[/tex]
