Answer:
108.217 °
Explanation:
Day of year = 356 = d (Considering year of 365 days)
Latitude of Tropic of Cancer = 23.5 °N
Declination angle
δ = 23.45×sin[(360/365)(d+284)]
⇒δ = 23.45×sin[(360/365)(356+284)]
⇒δ = 5.2832 °
Altitude angle at solar noon
90+Latitude-Declination angle
= 90+23.5-5.2832
= 108.217 °
∴ Altitude angle of the Sun as seen from the tropic of cancer on December 22 is 108.217 °
