Answer:
5y -x=8
Step-by-step explanation:
We have given [tex]x^2+y^2+xy=0[/tex]
Differentiating this function with respect to x
[tex]2x+2y+x\frac{dy}{dx}+y=0[/tex]
At point (2,2)
[tex]2\times 2+2\times 2+2\times \frac{dy}{dx}+2=0[/tex]
[tex]\frac{dy}{dx}= -5[/tex]
that is m= -5
The equation of normal is [tex]]\frac{y-y_1}{x-x_1}=\frac{-1}{m}[/tex
[tex]\frac{y-2}{x-2}=\frac{-1}{-5}[/tex]
5y-x=8 this is the equation of normal
