Answer:
The above function will get the minimum value at the value of p =14 ....
Step-by-step explanation:
Take the derivative of the given function with p and equate to zero to minimize the given function.
c(p) = p^2 - 28p + 250
(d/dp) c(p) = (d/dp)p^2 - 28p + 250 = 2p-28
(d/dp) c(p) = 0
2p-28 = 0
Move the constant to the R.H.S
2p = 28
Divide both sides by 2
2p/2 = 28/2
p = 14
The above function will get the minimum value at the value of p =14 ....
