lol1231265
lol1231265 lol1231265
  • 07-08-2019
  • Mathematics
contestada

Please help me. I need help

Please help me I need help class=

Respuesta :

Gasaqui
Gasaqui Gasaqui
  • 11-08-2019

Answer:

[tex]\sqrt[7]{(6x)^{3}}[/tex]

Step-by-step explanation:

Remembering

[tex]\sqrt[n]{x} = x^{\frac{1}{n}}[/tex]

so

[tex](6x)^{\frac{3}{7}} = \sqrt[7]{(6x)^{3}}[/tex]

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