Answer:
b) 70°C
Explanation:
Given that super heat temperature at 101.325 KPa= 170°C.
We know that saturation temperature at 101.325 KPa is 100°C.
So
Degree of super heat =Super heat temperature - saturation temperature ( at constant pressure)
Now by putting the values
Degree of super heat=170-100
Degree of super heat=70°C.
So our option b is right.
