Answer:
Option B is correct.
Step-by-step explanation:
(x+2<5) U (x-7>-6)
Solving and finding the value of x and then taking Union of both answers
x+2 < 5
x < 5-2
x < 3
x-7 > -6
x > -6 + 7
x > 1
So, x < 3 or x > 1
{x|x<3 or x > 1}
Option B is correct.
