Step-by-step explanation:
Taking left hand side:
[tex]\frac{1+tan\ x}{sin\ x+cos\ x}\\=\frac{1+\frac{sin\ x}{cos\ x} }{sin\ x+cos\ x}\\=\frac{\frac{cos\ x+sin\ x}{cos\ x} }{sin\ x+cos\ x}\\=\frac{cos\ x+sin\ x}{cos\ x} * \frac{1}{sin\ x+cos\ x}\\=\frac{1}{cos\ x}[/tex]
1/cos x is equal to sec x.
So,
[tex]\frac{1}{cos\ x} = sec\ x[/tex]
Hence proved ..
