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A pole vaulter takes 1.3 seconds to fall from peak height to the landing mat. What is his vertical velocity at contact with the mat?

Respuesta :

hdawg7797

[tex]12.75 \frac{m}{s}[/tex]

Assuming vertical acceleration of [tex]9.81 \frac{m}{s^2}[/tex], the speed after x seconds of falling is [tex]9.81x \to 9.81(1.3) = 12.75[/tex]

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