elissalpantoja67 elissalpantoja67
  • 08-07-2019
  • Chemistry
contestada

If 1.216g of cobalt metal react with 0.495g of oxygen gas what is empirical formula of the cobalt oxide product

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cristisp93
cristisp93 cristisp93
  • 20-07-2019

First you divide each mass by the mass number of the element:

Cobalt        1.216 / 59 = 0.02

Oxygen      0.495 / 32 = 0.03

Then the result is divided by the lowest number:

Cobalt        0.02 / 0.02 = 1

Oxygen      0.03 / 0.02 = 1.5

After that you multiply with a number to obtain an integer number:

Cobalt        1 × 2 = 2

Oxygen      1.5 × 2 = 3

The empirical formula of the oxide:  

Co[tex]_{2}[/tex]O[tex]_{3}[/tex]

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