Answer:
r = 2
Step-by-step explanation:
[tex]a_n-\text{geometric sequence}\\\\a_1,\ a_2,\ a_3,\ ...,\ a_n-\text{terms of a geometric sequence}\\\\r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac{a_4}{a_3}=\hdots=\dfrac{a_n}{a_{n-1}}-\text{common ratio}\\\\\text{We have:}\ a_1=2,\ a_2=4,\ a_3=8,\ a_4=16,\ ...\\\\\text{The common ratio:}\\\\r=\dfrac{4}{2}=\dfrac{8}{4}=\dfrac{16}{8}=2[/tex]
