Answer: 0.0902
Step-by-step explanation:
Given : The average number of phone inquiries per day at the poison control center : [tex]\lambda=2[/tex]
The Poisson distribution function is given by :-
[tex]\dfrac{e^{-\lambda}\lambda^x}{x!}[/tex]
Then , the probability that it will receive exactly 4 calls on a given day is given by (Put [tex]x=4[/tex] and [tex]\lambda=2[/tex]) :-
[tex]\dfrac{e^{-2}2^4}{4!}=0.09022352215\approx0.0902[/tex]
Hence, the required probability : 0.0902
