Answer:
(i) 0.05 mol/L; (ii) 5 g/L
Explanation:
We can use the dilution formula:
c1V1 = c2V2
Data:
c1 = 0.5 mol/L; V1 = 100 cm3
Added water = 900 cm3
Calculations:
(i) Moles per litre
V2 = 100 + 900 = 1000 cm^3 = 1 L
0.5 × 100 = c2 × 1000
50 = c2 × 1000
c2 = 0.05 mol/L
(ii) Grams per litre
c2 = 0.05 mol/L × (105.99 g/1 mol) = 5 g/L
