Rosaa4815 Rosaa4815
  • 06-05-2016
  • Chemistry
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952 grams of ammonium carbonate are dissolved to make 1750 mL of solution

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taskmasters
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  • 13-05-2016
(%m/v) =mass of solute (in g) / volume of solution (in mL) x 100
       
            = 952 g (NH4)2CO3 / 1750 mL x 100
    
            = 0.544 x 100
       
(%m/v) = 54.4 g /mL or 54.4% concentration of ammonium carbonate 
                                                solution



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