Respuesta :

[tex]\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{4}{ h},\stackrel{1}{ k})\qquad \qquad radius=\stackrel{2}{ r} \\\\\\ (x-4)^2+(y-1)^2=2^2\implies (x-4)^2+(y-1)^2=4[/tex]

Otras preguntas