accurate73 accurate73
  • 07-06-2019
  • Mathematics
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jdoe0001 jdoe0001
  • 07-06-2019

[tex]\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{-4})~\hspace{10em} slope = m\implies \cfrac{3}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-4)=\cfrac{3}{5}(x-2)\implies y+4=\cfrac{3}{5}(x-2) \\\\\\ y+4=\cfrac{3}{5}x-\cfrac{6}{5}\implies y=\cfrac{3}{5}x-\cfrac{6}{5}-4\implies y=\cfrac{3}{5}x-\cfrac{26}{5}[/tex]

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