Answer:
[tex]\frac{(k+5)}{12(k+2)}[/tex]
Step-by-step explanation:
We need to perform the folowing operation:
[tex]\frac{k^{2} + 3k - 10 }{36}[/tex] × [tex]\frac{3}{k^{2} -4 }[/tex]
Factorizing we have:
[tex]\frac{(k-2)(k+5)}{36}[/tex] × [tex]\frac{3}{(k+2)(k-2)}[/tex]
Simplifying, we get:
[tex]\frac{(k+5)}{12(k+2)}[/tex]
