Answer:
[tex]\frac{4}{5}[/tex]
Step-by-step explanation:
Given
sinΘ = [tex]\frac{3}{5}[/tex] = [tex]\frac{opposite}{hypotenuse}[/tex]
Then the hypotenuse = 5 and one leg of the right triangle is 3
Using Pythagoras' identity to find the second leg (x)
x² + 3² = 5²
x² + 9 = 25 ( subtract 9 from both sides )
x² = 16 ⇒ x = 4
cosΘ = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{4}{5}[/tex]
