Answer:
[tex]\frac{6\left(x+4\right)\left(x+3\right)}{24\left(x-3\right)\left(x+4\right)}=\frac{x+3}{4\left(x-3\right)}[/tex]
[tex]\mathrm{Cancel\:the\:common\:factor:}\:6\\=\frac{\left(x+4\right)\left(x+3\right)}{4\left(x-3\right)\left(x+4\right)}\\\mathrm{Cancel\:the\:common\:factor:}\:x+4[/tex]
Hope this helps!!!
[tex]Sofia[/tex]
