pg22 pg22
  • 07-05-2019
  • Mathematics
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Rewrite sin^4x so that it involves on the first power of cosine

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LammettHash
LammettHash LammettHash
  • 07-05-2019

Use the half-angle identities.

[tex]\sin^2x=\dfrac{1-\cos2x}2[/tex]

[tex]\implies\sin^4x=\left(\dfrac{1-\cos2x}2\right)^2=\dfrac{1-2\cos2x+\cos^22x}4[/tex]

[tex]\cos^2x=\dfrac{1+\cos2x}2[/tex]

[tex]\implies\sin^4x=\dfrac{1-2\cos2x+\frac{1+\cos4x}2}4=\dfrac{3-4\cos2x+\cos4x}8[/tex]

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