yash2006parmar
yash2006parmar yash2006parmar
  • 09-04-2019
  • Mathematics
contestada

If ab = 8 and a^2+b^2=16, then what is the value of (a+b)^2?

Respuesta :

stephaniechiriboga stephaniechiriboga
  • 09-04-2019

Answer:

256

Step-by-step explanation:

(a+b)^2

(8+8)^2

(16)^2

256

Answer Link
jimrgrant1 jimrgrant1
  • 09-04-2019

Answer:

32

Step-by-step explanation:

The expansion of (a + b)² is

(a + b)² = a² + 2ab + b²

           = a² + b² + 2ab ← substitute in relevant values

           = 16 + 2 × 8 = 16 + 16 = 32

Answer Link

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