Answer:
[tex](3x+3y+9)\ ft^{2}[/tex]
Step-by-step explanation:
Let
x------> the length of the original play space
y-----> the width of the original play space
we know that
The area of the original play space is equal to
[tex]A=xy[/tex]
The area of the new play space is equal to
[tex]An=(x+3)(y+3)\\An=xy+3x+3y+9[/tex]
Find the difference
[tex]An-A=(xy+3x+3y+9)-(xy)\\An-A= (3x+3y+9)\ ft^{2}[/tex]
