use the quadratic formula and plug in the coefficients
[tex]3x - 9 {x}^{2} = - 10 \\ - 9 {x}^{2} + 3x + 10 = 0 \\ b = 3 \\ a = - 9 \\ c = 10 \\ - \frac{3 + \sqrt{ {3}^{2} - 4( - 9)(10) } }{2( - 9)} \\ \frac{ - 3 + \sqrt{9 + 360} }{ - 18} \\ \frac{ - 3 + 3 \sqrt{41} }{{ - 18} } \\ \frac{ - 1 + \sqrt{41} }{ - 6} [/tex]
I wasn't able to the plus or minus sign in so I just used the plus sign you can look up the quadratic formula online
