Answer:
Reducing the volume of a contained gas by one third, while holding temperature constant, causes pressure to increase by 3.0 times.
Explanation:
- Boyle’s Law : At constant temperature, the volume of a given quantity of a gas varies inversely with its pressure.
- It is clear from the data that V ∝ 1/P.
So, for two different values of both P and V:
∴ P₁V₁ = P₂V₂.
∵ V₂ = 1/3V₁
∴ P₂ = P₁V₁/V₂ = P₁V₁/(1/3V₁) = 3P₁.
