Answer:
83.3 kHz
Explanation:
The frequency of a waveform is equal to the reciprocal of its period:
[tex]f=\frac{1}{T}[/tex]
where
f is the frequency
T is the period
In this problem, we have
[tex]T=12 \mu s=12\cdot 10^{-6} s[/tex]
so, the frequency of the waveform is
[tex]f=\frac{1}{12 \cdot 10^{-6} s}=8.33\cdot 10^4 Hz[/tex]
And by converting into kiloHertz,
[tex]f=8.33\cdot 10^4 Hz=83.3 kHz[/tex]
