Answer:
326.4 mC
Explanation:
The relationship between charge, capacitance and voltage in a capacitor is given by
[tex]C=\frac{Q}{V}[/tex]
where
C is the capacitance
Q is the charge
V is the voltage
In this problem, we have
C = 34 mF is the capacitance
V = 9.6 V is the voltage
Re-arranging the equation and substituting the numbers, we find the charge stored in the capacitor:
[tex]Q=CV=(34 mF)(9.6 V)=326.4 mC[/tex]
