carlie23
carlie23
10-03-2019
Mathematics
contestada
Find the area of the rhombus
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Kamikazeminem
Kamikazeminem
10-03-2019
[tex]TQ = \sqrt{ {PQ}^{2} - {PT}^{2} } = \sqrt{{20}^{2} - {16}^{2} } = \sqrt{144} = 12\: mm \\ Area:16 \times 12 \times 2 = 384\: {mm}^{2}[/tex]
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