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Kamikazeminem

[tex]Rectangle \: PQRS \: has \: PQ=QR\Rightarrow PQRS \: is \: a \: square \Rightarrow QR = SR \\ {SQ}^{2} = {SR}^{2} + {QR}^{2} = 2{SR}^{2} \\ \Leftrightarrow SR = \sqrt{ \frac{{SQ}^{2}}{2} } = \sqrt{ \frac{ {(6 \sqrt{2} )}^{2} }{2} } = \sqrt{ \frac{72}{2} } = \sqrt{36} = 6 \\ \Rightarrow b) \: 6[/tex]

Cutiepatutie

Given rectangle PQRS with PQ=QR, PQ=SP, and SQ=6√2. Find SR, SR is 6.

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