Answer: [tex]\bold{\dfrac{1}{x+1}}[/tex]
Step-by-step explanation:
[tex]\underline{f(x)}: \underline{\quad x+6\qquad}\\g(x):x^2+7x+6\\\\\\\text{Factor the denominator}:\\\underline{f(x)}: \underline{\quad x+6\qquad}\\g(x):(x+6)(x+1)\\\\\\\text{cancel out the common factor (x+6)}:\\\underline{f(x)}: \underline{\quad 1\quad}\\g(x):\ x+1\\[/tex]
