Desigurl
Desigurl
10-02-2019
Mathematics
contestada
PLEASE HELP!!!!!!!!!!!
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5naka
5naka
11-02-2019
by using identity sin²θ=1 - cos²θ
3sin²θ = 4cosθ - 1
3(1 - cos²θ) = 4cosθ - 1
3 - 3cos²θ = 4cosθ - 1
3cos²θ + 4cosθ - 4 = 0
(3cosθ - 2)(cosθ + 2) = 0
cosθ = ⅔
θ = 48.19° or θ = 311.81°
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