[tex]\bf \textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360}~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\[-0.5em] \hrulefill\\ r=24\\ \theta =160 \end{cases}\implies A=\cfrac{(160)(\pi )(24)^2}{360} \\\\\\ A=256\pi\implies A\approx 804.25[/tex]
