Given value is
Solute=100g of AlF3
Solution= 1200ml
Formula is;
Molarity = mole of solution/ solution in liter
We have to find moles first.
For this purpose apply formula
No.of mole=mass in g/ molar mass
Mass= 100g
Molar mass = 83.9767g/mol
No of mole = 100/83.9767
= 1.191mol
Now convert solution into liter
1200ml= 1200/1000= 1.2L
Now put these values in molarity formula
Molarity= no.of mole/ solution in liter
= 1.191mole of AlF3/1.2L of water
= 0.9925M of AlF3
