[tex]y=\dfrac{1}{2}x-5\\\\for\ x=0\to y=\dfrac{1}{2}(0)-5=0-5=-5\to(0,\ -5)\\\\for\ x=4\to y=\dfrac{1}{2}(4)-5=2-5=-3\to(4,\ -3)\\\\y=-\dfrac{1}{3}x\\\\for\ x=0\to y=-\dfrac{1}{3}(0)=0\to(0,\ 0)\\\\for\ x=3\to y=-\dfrac{1}{3}(3)=-1\to(3,\ -1)\\\\Look\ at\ the\ picture.\\\\Answer:\ \boxed{one\ solution\ (6,\ -2)}[/tex]
