luiscarloscanezr luiscarloscanezr
  • 07-01-2019
  • Mathematics
contestada

What is the value of n in the equation 2.3 × 109 = (1 × 103)(2.3 × 10n)?

Respuesta :

dtaylor595670
dtaylor595670 dtaylor595670
  • 16-04-2021

Answer:

10^-3

Step-by-step explanation:

Answer Link
deepakrai138
deepakrai138 deepakrai138
  • 22-12-2021

The value of n is 0.1058.

Given,  [tex]2.3 \times 109 = (1 \times103)(2.3 \times10 n)[/tex]

[tex]250.7=103\times2.3\times10n[/tex]

[tex]10n=\frac{250.7}{103\times2.3}[/tex]

[tex]10n=\frac{250.7}{236.9}[/tex]

[tex]10n=1.058[/tex]

[tex]n=\frac{1.058}{10}[/tex]

[tex]n=0.1058[/tex]

So the value of n is 0.1058.

For more details on equations follow the link below:

https://brainly.com/question/17954847

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