Answer:
B. 14
Step-by-step explanation:
The sum of infinite geometric series is given by
[tex]\frac{a}{1-r}[/tex]
0.126126126... = [tex]\frac{126}{1000}+\frac{126}{1000000}+\frac{126}{1000000000}[/tex]
Here a =126/1000, r= 1/1000
0.126126126... = [tex]\frac{126/1000}{1-1/1000}[/tex] =126/999 = 14/111
∴ 0.126126126... = 14/111
So, the numerator of the reduced fraction is 14.
