we are given
basketball player Chauncey Billups of the Detroit Pistons makes free throw shots 88% of the time
so, probability of making shot is
=88%
so, p=0.88
To find the probability of missing first shot and making the second shot
so, we can use formula
probability = p(1-p)
now, we can plug values
we get
[tex]probability=0.88(1-0.88)[/tex]
So, the probability that he misses his first shot and makes the second is 0.1056........Answer
