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  • 07-11-2018
  • Mathematics
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Find the center radius of the circle x^2 + y^2 + 3/4x + 5/3y - 1/2 = 0

Find the center radius of the circle x2 y2 34x 53y 12 0 class=

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Аноним Аноним
  • 07-11-2018

Answer:

(-3/8, -5/6) ; √(769)/24  Choice B

Step-by-step explanation:

Convert this to  standard form   ( (x - a)^2 + (y - b)^2 = r^2  where a,b is the centre and r = radius) :-

x^2 + y^2 + 3/4 x + 5/3 y - 1/2 = 0

x^2 + 3/4 x + y^2 + 5/3 y  = 1/2

(x + 3/8)^2 - (3/8)^2 + ( y + 5/6)^2 - (5/6)^2 = 1/2

( x + 3/8)^2 + ( y + 5/6)^2 = 1/2 + 9/64 +  25/36

( x + 3/8)^2 + ( y + 5/6)^2 =  769/576

So comparing this with the above standard from :-

center = (-3/8, -5/6) and radius is sqrt (769/576)  = sqrt 769 / 24

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