n, n + 2, n + 4 - three consecutive odd integers
the first is 33 less than twice the second
n - 33 = 2(n + 2) use distributive property
n - 33 = (2)(n) + (2)(2)
n - 33 = 2n + 4 add 33 to both sides
n = 2n + 37 subtract 2n from both sides
-n = 37 change the signs
n = 37
n + 2 = 37 + 2 = 39
n + 4 = 37 + 4 = 41
Answer: 37, 39, 41
