The point-slope form:
[tex]y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have the points (4, 5) and (-3, -1). Substitute:
[tex]m=\dfrac{-1-5}{-3-4}=\dfrac{-6}{-7}=\dfrac{6}{7}\\\\y-(-1)=\dfrac{6}{7}(x-(-3))\\\\\boxed{y+1=\dfrac{6}{7}(x+3)}[/tex]
