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  • 09-10-2018
  • Mathematics
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Аноним Аноним
  • 09-10-2018

The sum of the inner angles of a polygon with n sides is [tex] 180(n-2) [/tex]

Since your polygon has 6 sides, the sum of its inner angles has to be

[tex] 180(6-2) = 180 \cdot 4 = 720[/tex]

On the other hand, the sum of its inner angles is

[tex] 75+132+113+108+160+x = 588+x [/tex]

And it has to be 720, so we have

[tex]588+x=720 \iff x = 720-588 = 132 [/tex]

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