justicemjohnson1726 justicemjohnson1726
  • 08-10-2018
  • Mathematics
contestada

-6g + 3g + 12 > -18

a.
g < 2
b.
g > 2
c.
g < 10
d.
g > 10

a.
g < 2
b.
g > 2
c.
g < 10
d.
g > 10

Respuesta :

Аноним Аноним
  • 08-10-2018

First of all, you can sum the two terms involving g on the left hand side:

[tex] -6g + 3g + 12 > -18 \iff -3g + 12 > -18 [/tex]

Subtract 12 from both sides:

[tex] -3g > -30 [/tex]

Divide both sides by -3: note that since we're dividing by a negative number, we must invert the inequality sign:

[tex] g< 10 [/tex]

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