For this case we have the following polynomial:
[tex]y^2 + 6y - 16[/tex]
We must find two numbers that comply with:
1) The algebraic sum of the numbers is equal to 6.
2) The multiplication of the numbers is equal to -16.
Therefore, factoring the polynomial we have:
[tex](y + 8) (y-2)[/tex]
Answer:
The factored expression is:
b. (y + 8) (y - 2)
