we are given
[tex] f(x)=\frac{x^2+5x+6}{x+3} [/tex]
Firstly , we will factor numerator numerator
[tex] f(x)=\frac{(x+3)(x+2)}{x+3} [/tex]
we can see that both numerator and denominator has common term as x+3
so, there will be hole at x+3=0
and we know that hole is a type of discontinuity
so, discontinuity would be at
[tex] x=-3 [/tex]............Answer
