chancek99 chancek99
  • 08-08-2018
  • Mathematics
contestada

subtract c/c^2+5c+6 - 2/c^2+3c+2

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Аноним Аноним
  • 08-08-2018

factor the denominators:-

c^2 + 5c + 6 = (c + 2)(c + 3)

c^2 + 3c + 2 = (c + 2)(c + 1)

so the LCM = (c + 2)(c + 1)(c + 3)

Subtracting the fractions:-

= c(c + 1) - 2(c + 3) / (c + 1)(c + 2) (c + 3)

= c^2 - c - 2) / (c + 1)(c + 2) (c + 3)

= (c - 2)(c + 1) / (c + 1)(c + 2) (c + 3)

= (c - 2) / (c + 2)(c + 3) (answer)

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